(5x+7)(5x^2-16x+12)=0

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Solution for (5x+7)(5x^2-16x+12)=0 equation: 


Simplifying
(5x + 7)(5x2 + -16x + 12) = 0

Reorder the terms:
(7 + 5x)(5x2 + -16x + 12) = 0

Reorder the terms:
(7 + 5x)(12 + -16x + 5x2) = 0

Multiply (7 + 5x) * (12 + -16x + 5x2)
(7(12 + -16x + 5x2) + 5x * (12 + -16x + 5x2)) = 0
((12 * 7 + -16x * 7 + 5x2 * 7) + 5x * (12 + -16x + 5x2)) = 0
((84 + -112x + 35x2) + 5x * (12 + -16x + 5x2)) = 0
(84 + -112x + 35x2 + (12 * 5x + -16x * 5x + 5x2 * 5x)) = 0
(84 + -112x + 35x2 + (60x + -80x2 + 25x3)) = 0

Reorder the terms:
(84 + -112x + 60x + 35x2 + -80x2 + 25x3) = 0

Combine like terms: -112x + 60x = -52x
(84 + -52x + 35x2 + -80x2 + 25x3) = 0

Combine like terms: 35x2 + -80x2 = -45x2
(84 + -52x + -45x2 + 25x3) = 0

Solving
84 + -52x + -45x2 + 25x3 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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